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An object moves in a straight line with deceleration whose magnitude varies with velocity s `3v^(2/3)`. If at an initial point, the velocity is 8/m sec, then the distance travelled by the object before it stops is

A

2m

B

4m

C

6m

D

8m

Text Solution

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The correct Answer is:
B
`V_0= 8 m//sec`
` ds = (- V_(-0)^(2))/(2a) = (-(8)^2)/(2 (9.8) ) = 3.265`
`therefore ds ~~ 4m`
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