A current carrying conductor obeys Ohm's law (V = RI). If the current passing through the conductor is `I = (5 pm 0.2)` A and voltage developed is` V =( 60 pm 6)` then find the percentage of error is resistance, R

Options

A. 18
B. 6
C. 14
D. 2

Answer

C

Explanation

Given,
For a current carrying conductor,
`V = Ri" "…(1)`
Current through conductor, `I = (5 pm 0.2)A`
Here, `Delta I =0.2A`
Volatage developed, `V = (60 pm 6) V`
Here, `Delta V= 6V`
From equation (1),
`%` error in resistince `R = ((Delta V)/(V) + (Delta I)/(I))xx 100`
`(Delta R)/(R) xx 100= ((6 )/(60) + (0.2)/(5)) xx100`
` = ((1)/(10) + (2)/(50)) xx 100`
`= 14%`
`therefore (Delta R)/(E) xx 100= 14%`