If an air bubble rises from the bottom of a mercury tank to the top its volume becomes `1(1/2)` times. When normal pressure is 76 cm of Hg then the depth of the Hg tank is
A
38 cm
B
132 cm
C
76 cm
D
49 cm
Text Solution
Verified by Experts
The correct Answer is:
B
Topper's Solved these Questions
MOCK TEST 2
SIA PUBLICATION|Exercise Chemistry|1 Videos
MOCK TEST 1
SIA PUBLICATION|Exercise PHYSICS|27 Videos
MOTION IN A STRAIGHT LINE AND A PLANE
SIA PUBLICATION|Exercise MCQ|12 Videos
Similar Questions
Explore conceptually related problems
An air bubble rises from the bottom of a water tank of height 5 m. If the initial volume of the bubble is 3" mm"^(3) , then what will be its volume as it reaches the surface? Assume that its temperature does not change. [g=9.8m//s^(2),1" atm "=10^(5)” Pa, density of water"=1" gm"//"cc"]
When air bubble comes from bottom to the top of a lake , Its radius becomes n- times . If temperature remains constant through out the lake . The depth of lake . Is (P_0 ( n^(x+1) -1) + ( xT )/(R ) (n^(x )-1))/( rho g) . Find x
An air bubble released at the bottom of a lake, rises and on reaching the top, its radius found to be doubled. If the atmospheric pressure is equivalent to H metre of water column, find the depth of the lake (Assume that the temperature of water in the lake is uniform)