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If n(c ) and n(h) are electron and hole ...

If `n_(c ) and n_(h)` are electron and hole concentralious in an extrinsic semiconductor and `n_(i)` is electron concentrations in an intrinsic semiconductor, then

A

`(n_(e)/n_(h)) = n_(i)`

B

`(n_(e)+n_(h)) = n_(i)`

C

`(n_(e) - n_(h)) = n_(i)^(2)`

D

`(n_(e)n_(h)) = n_(i)^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
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