A particle is projected with velocity `2 sqrt(gh)` and at an agnle `60^(@)` to the horizontal so that it just clears two walls of equal height h which are at a distance 2h from each other. The time taken by the particle to travel between these two wall is

Options

A. `2sqrt((2h))/(g)`
B. `sqrt((h))/(2g)`
C. `2sqrt((h))/(g)`
D. `sqrt((h))/(g)`

Answer

C

Explanation

Velocity of particle `=2sqrt(gh)`
Angle `(theta)=60^@`
Distance =2h
`2h=2sqrt(gh)cos 60^@ t`
`sqrt(h)=sqrt(g) xx(1)/(2)t`
`t=2sqrt((h)/(g))`.