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A soap bubble of radius 1.0 cm is formed...

A soap bubble of radius 1.0 cm is formed inside another soap bubble of radius 2.0 cm The radius of an another soap bubble which has the same pressure difference as that between the inside of the smallar and outside of large snap bubble, in metres is

A

`6.67xx10^(-3)`

B

`3.34xx10^(-3)`

C

`2.23xx10^(-30`

D

`4.5xx10^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`R_1=2.0 cm, R_2=1.0 cm`
`rArr r =(R_1 R_2)/(R_1+R_2)`
`=(2xx1)/(2+1)=(2)/(3) =0.6 cm = 6.6 xx 10^(-3) m`
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