The ratio of energies of emtiied radiation by a black body at 600 K and 900 K when the surrounding temperature is 300, is

Options

A. `(5)/(16)`
B. `(7)/(16)`
C. `(3)/(16`
D. `(9)/(16)`

Answer

C

Explanation

The energy radiated by black body is given by.
`(Q)/(At)prop(T^(4)-t^(4))`
`(Q_(1))/(Q_(2))=((600)^(4)-(300)^(-4))/((900)^(4)-(300)^(4))=(3)/(16)`