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Force F is given by the equation F = X/L...

Force F is given by the equation `F = X`/Linear density Then dimension of X are

A

`M^(2)L^(0)T^(-2)`

B

`M^(0)L^(0)T^(-1)`

C

`L^(2)T^(-2)`

D

`M^(0)L^(2)T^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`F = X`/Linear density
`X = F xx` Linear density `= [MLT^(-2)][ML^(-1)] = [M^(2)L^(0)T^(-2)]`
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Knowledge Check

  • If the force is given by F = at + bt^(2) with t as time. The dimensions of a and b are

    A
    `[MLT^(-4)], [MLT^(-2)]`
    B
    `[MLT^(-3)], [MLT^(-4)]`
    C
    `[ML^(2)T^(-3)], [ML^(2)T^(-2)]`
    D
    `[ML^(2)T^(-3)], [ML^(3)T^(-4)]`

  • A force F is given by F at + bt^(2) where t is time. What are dimensions of 'a' and 'b'?

    A
    `MLT^(-3)` and `ML^(2)T^(4)`
    B
    `MLT^(-3)` and `MLT^(-4)`
    C
    `MLT^(-1)` and `MLT^(0)`
    D
    `MLT^(-4)` and `MLT^(1)`

  • A force F is given by F = at +bt^2 , where t' is time. What are dimensions of 'a' and 'b' ?

    A
    `MLT^(-3)` and `ML^2T^4`
    B
    `MLT^(-3)` and `MLT^(-4)`
    C
    `MLT^(-1) ` and `MLT^0`
    D
    `MLT^(-4) ` and `MLT^1`

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