Dimensions of ohm are same as (h = Planck's constant,e = charge)

Options

A. `h/e`
B. `h^(2)/e`
C. `h/e^(2)`
D. `h^(2)/e^(2)`

Answer

C

Explanation

Dimensional formula for planck's constant, `h = [ML^(2)T^(-1)]` and charge e = IT
`:.` Dimensional formula of ohm is given by, `h/e^(2) = ML^(2)T^(-1)/I^(2)T^(2) = M L^(2) T^(-3) I^(-2)`