When a big drop of water is formed from n small drops of water, the energy loss is 3E, where, E is the energy of the bigger drop. If the radius of the bigger drop is R and r is the radius of the smaller drop, then number of smaller drops (n) is

Options

A. `4R/r^(2)`
B. `4R/r`
C. `2R^(2)/r`
D. `4R^(2)/r^(2)`

Answer

d

Explanation

Loss of energy by bigger drop = the energy of n small drops-the energyy of the bigger drop
`3xx4piR^(2)xx T=nxx4pirr^(2)xxT-4piR^(2)xxT`
`n=(16piR^(2)T)/(4pir^(2)T)=4R^(2)/r^(2)`