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Two coherent sources of intensity ratio ...

Two coherent sources of intensity ratio `9 : 4` produce interference. The intensity ratio of maxima and minima of the interference pattern is

A

`13:5`

B

`5:1`

C

`25:1`

D

`3:2`

Text Solution

Verified by Experts

The correct Answer is:
c
`I_(max)/I_(min)=(sqrt(I_(1))+sqrt(I_(2)))^(2)/ (sqrt(I_(1))-sqrt(I_(2)))^(2)`
`= ( sqrt(I_(1)/ sqrt(I_(2))+1))^(2)/ ( sqrt(I_(1)/ sqrt(I_(2)) - 1))^(2)`
`=(3/2 +1)^(2)/(3/2 -1)^(2)`
` therefore I_(max):I_(min)=25:1`
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Knowledge Check

  • Light waves producing interference have their amplitudes in the ratio 3 : 2 . The intensity ratio of maximum and minimum of interference fringes is

    A
    `36 : 1`
    B
    `9 : 4`
    C
    `25 : 1`
    D
    `6 : 4`

  • If the amplitude ratio of two source producing interference is 3.5 ,the ratio of intensities of maxima and minima is

    A
    `25:16`
    B
    `5:3`
    C
    `16:1`
    D
    `25:9`

  • If the amplitude ratio of two sources producing interference is 3.5, the ratio of intensities of maxima and minima is

    A
    `25 : 16`
    B
    `5:3`
    C
    `16:1`
    D
    `25:9`

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