In two separate collisions, the coefficient of restitutions d) A is false but B is true e and e  are in the ratio 3: 1. In the first collision the relative velocity of approach is twice the relative velocity of separation, then the ratio between relative velocity of approach and the relative velocity of separation in the second collision is,

Options

A. `1:6`
B. `2:3`
C. `3:2`
D. `6:1`

Answer

d

Explanation

Coffcient of restitution,
`e=("relavtive velocity of seperation")/(r"elavtive velocity of approach")`
`e_(1)=1/2`
`e_(1)/e_(2)=3/1`
`e_(2)=e_(1)/3=1/2xx1/3=1/6`
therefore ration of realative velocity of apporach to realative velocity of seperation =6/1=6:1