A body is moving up an inclined plane of angle ` theta` with an initial kinetic energy E. The coefficient of friction between the plane and the body is `mu`. The work done against friction before the body comes to rest is

Options

A. `(mucostheta)/(Ecostheta+sintheta)`
B. E
C. `(muEcostheta)/(mucostheta+sintheta)`
D. `(muEcostheta)/(mucostheta+sintheta)`

Answer

b

Explanation

a=g(mucostheta+sintheta) from the law of equation of motion
From the law of equation of motion
`v^(2) =u^(2)+2as`
`-u^(2)=2as[v=0]`