A bullet of mass x moves with a velocity y, hits a wooden block of mass z, at rest and gets embedded in it. After collision if the wooden block with bullet in it moves the velocity is

Options

A. `x/(x+z)y`
B. `x+z/(x)y`
C. `z/(x+y)y`
D. `x+y/(z)y`

Answer

a

Explanation

According to law of Conservation of momentum,
` m_(1)u_(1)+m_(2) u_(2)=(m_(1)+m_(2))v [therefore v_(1)=v_(2)=v]`
`x xxy+zxx0=(x+z)v`
`v=xy/x+z`