If A is the areal velocity of a planet of mass M, its angular momentum is

Options

A. `(M)/(A)`
B. 2MA
C. `A^(2)M`
D. `AM^(2)`

Answer

(b)

Explanation

Areal velocity , `A=(1)/(2)R^(2)omega`
`MA=(1)/(2)MR^(2)omega impliesMA=(1)/(2)Iomega` ` [becauseI=MR^(2)]`
`MA=(1)/(2)L` `[becauseL=Iomega]`
`L=2MA`