The ratio between kinetic and potential enerdies of a body executing simple harmonic motion,when its is at a distance of 1/N of its amplitude from the mean potion is,

Options

A. `N^2+1`
B. `1/N^2`
C. `N^2`
D. `N^2-1`

Answer

d

Explanation

`KE=1/2momega[A-(A/N)^2]`
`PE=1/2momega^2 A^2/N^2`
From the equation (1) and (2),
`(KE)/(PE)= (1/2momega(A-(A/N)^2))/(1/2momegaA^2/N^2`
`=(A^2/N^2(N^2-1))/(A^2/N^2)`
`N^2-1`