Two particle A and B of mases 'm' and 2'm' are suspended from springs of force constants K_1 and K_2. During their oscillation, if their maximum velocities are equal, then the ratio of amplitude of A and Bis,

Options

A. `sqrt(k^2/k^(1)`
B. `sqrt(k^2/(2k_1)`
C. `sqrtk^2/(k_1)`
D. `sqrtk^2/(k_1)`

Answer

b

Explanation

`V_max=Aomega=Asqrtk/m`
`m_1=m,m_2=2m,` Force constant`K_1,K_2`
`A_Asqrt(k_1)/m=A_bsqrt(k_2)/(2m)`
`A_A/B_B=sqrt(K_2)/(2K_1)`