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The time period of a simple harmonic mot...

The time period of a simple harmonic motion is 8 s At t=0. it is at the mean position.The ratio of the distance travelled bi it in the first and second seconds is,

A

1/2

B

`1/sqrt(2)`

C

`1/sqrt(2-1)`

D

`1/sqrt(3)`

Text Solution

Verified by Experts

The correct Answer is:
C


`y_2=A-A/sqrt2`
`(y_1)/(y_2)=(A/sqrt(2))/(A-A/sqrt2)=(A/sqrt2(2))/ ((A sqrt((2-1)))/sqrt2)=1/(sqrt2-1) `
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