THE magnitude of maximum accesleration is `pi` times that of maximum velocity of a simble harmonic oscillator The time period of the oscillator. The time period of the oscillator in second is,

Options

A. 4
B. 2
C. 1
D. 0.5

Answer

b

Explanation

Maximum acceleration,`a_max=Aomega^2,V_max=Aomega`
`therefore a_max=pi V_max`
`Aomega=pi Aomega`
`therefore omega=2pi`
`implies T=pi/omega`
`=(2pi)/pi`
`therefore T=2 s`