The time period of a simple pendulum is T. When the length is increased by 10 cm, its period is `T_1`. Then , relation between T,`T_1` and `T_2` is,

Options

A. ` 2/T^2=1/T^2+1/T^2`
B. ` 2/T^2=1/T^2+1/T^2`
C. ` 2 T^2=T_1^2 `T_2^2
D. `2 T_2=T_1^2 T_2^2`

Answer

c

Explanation

Time period of simple pendulum,
`T=2pisqrt(l/g)`
`T_1=2pisqrt(l+10)`/(G)`
`T_1^2+T_2^2=4pi^2[(l+10+l-10)/g]`
`therefore T_1^2+T_2^2=4PI^2[(2L
)/G]-2T^2`