An object is attached to the bottom of a light vertical spring and set vobrating. The maximum speed of the object is `15 cm s^-1` and the period is 628 milli-seconds The amplitude of the motion in cm is,

Options

A. 3
B. 2
C. 1.5
D. 1

Answer

c

Explanation

`V_max=15cms^-1,T=628` milli-sec.
`V_max= (V_maxT)/(2pi)`
`=(15xx628xx10^-3)/(2xx3.14`
`=1.5cm`