A body executes simple harmonic motion under the action of a force `F_1` with a time period `4/5 s`. If the force is changed to `F_1` and `F_2` it executes SHM with time period `3/5` s .If the both the forces `F_1` and `F_2` act simultaneously in the same direction on the body, its time period in seconds is,

Options

A. `12/25`
B. `24/25`
C. `35/24`
D. `25/12`

Answer

a

Explanation

If both forces act simultaneously, the time period,
`T=t_1t_2`
`t_4//5 s and t_2=3/5s`
`T=4/5xx3/5`
`12/25s`