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The total mechanical energy of a harmoni...

The total mechanical energy of a harmonic oscillator of A =1 m and force constant ` 200 Nm^-1 is 150j`. Then

A

The minimum PE is zero

B

The minimum PE is 100 j

C

The minimum PE is 50 j

D

The minimum PE is 150 j

Text Solution

Verified by Experts

The correct Answer is:
d
Since total enegy is 150 j, maximum PE or maximum KE will be 150 j.
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