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In the Young’s double slit experiment, t...

In the Young’s double slit experiment, the resultant intensity at a point on the screen is 75% of the maximum intensity of the bright fringe. Then the phase difference between the two interfering rays at that point is

A

`pi/6`

B

`pi/4`

C

`pi/3`

D

`pi/2`

Text Solution

Verified by Experts

The correct Answer is:
c

The phase difference between the two interfering rays is,
`implies ¾ (4a^(2))=3a^(2)`
`implies4a^(2)cos^(2) phi/2=3a^(2) [ because cos^(2)(phi/2)=3/4]`
`impliescos^(2)(phi/2)=3/4`
`impliesphi/2 = cos^(-1)(sqrt(3)/2)= pi/6`
`implies phi= pi/3`
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