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The sensitivity of a galvanometer that m...

The sensitivity of a galvanometer that measure current is decreased by `(1)/(40)` times bu using shunt resistance of `10Omega .`
Then , the value of the resistance of the galvanometer is

A

`400Omega`

B

`410Omega`

C

`30Omega`

D

`390Omega`

Text Solution

Verified by Experts

The correct Answer is:
D
`L_2= sqrt3Li, R_2 = 1.4 R_1`
For LCR circuit , resonating frequency , `f_circ = (1)/2pisqrtLC`
`f_circ propto(1)/sqrtL`
`(f_circ)_1/(f_0)_2=sqrt(L_2)/(L_1)`
`Rightarrow (f_circ)_1/(f_circ)_2 (f_circ)_1/(f_circ )2=sqrt(sqrt(3L_1)/L_1`
`therefore (f_circ)_2 = (f_circ)_1 ((i)/(3))^((1)/(4))`
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