In the given circuit, the angular frequency of the voltage source is `70xx10^(3) rad s^(-1)`. The circuit effectively behaves like,

Options

A. purely resistive circuit
B. Series R-L circuit
C. Series R-C cricuit
D. Series L-C circuit with R= 0

Answer

C

Explanation

Resistance ,`R = (pl)/(A)`
For 2.5m length , `R'= (pxx(2.5)/(Axx10)`
From ohms law, `r^3=iR= (2.5pi)/(10A)`
If length is increased by im, `R" = (pxxl)/(11xxA)`
From ohm's law `V" = 1R^n = (IpI)/(11A)`
Here , `V' = V"`
`(2.5pI)/(10A) = (IpI)/(11A)`
therefore `l= (2.5xx11)/(10) = 2.75m`