In a meter bridge experiment , the ratio of the left gap resistance to right gap resistance is 2:3 , the balance point form left is

Options

A. 60cm
B. 50cm
C. 40cm
D. 20cm

Answer

C

Explanation

`(Ig)/(I-Ig)=(S)/(G)`
Galvanometer current is 5% of total current
`I_g= 5%I`
Substituting in equation (1), we get ,
`((5I)/(100))/((I-(5I)/(100)))= (s)/(G)`
`therefore (5)/(95)= (s)/(G)Rightarrow S= (G)/(19)`