Two resistance of `400Omega` and `800Omega` are connected I series with 6 V battery of negligible internal resistance . A voltemeter of resistance `10000Omega` is used to measure the potential difference across `400Omega` The error in the measurement of potential difference in volt approximately is

Options

A. `0.03`
B. `0.02`
C. `0.03`
D. `0.05`

Answer

B

Explanation

WE know that `(E_a)/(E_B)= (l_A)/(l_B)`
`(1.08)/(E_B) = (400)/(440)`
`E= 1.188V`