When a resistor of `11Omega` is conntected in series with an electric cell, the current flwoing in it is `0.5` A. Instead, when a resistor of `5Omega` is conntected to the same electric cell in series, the current increase by `0.4` A , The internal resistance of the cell is

Options

A. `1.5Omega`
B. `2Omega`
C. `2.5Omega`
D. `3.5Omega`

Answer

A

Explanation

I=50cm, `A=1m^2,` `i=4A, v=2` (Given)
Resistivity, `P = (RA)/(I)`
`(V)/(i)xx(A)/(I)`
` = (2)/(4)xx(1xx(10^(-3))^2)/(50xx10^(-2)`
`1xx10^(-4)Omega-m`