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A galvanmeter has a resistance of 50Omeg...

A galvanmeter has a resistance of `50Omega` and a current of 0.01 A will cause full scale deflection . To converted this into an ammeter with full deflection for 5A , we have to connect approximately

A

`0.1Omega` in series

B

`0.1Omega` in parallel

C

`0.2Omega` in series

D

`0.2Omega`in parallel

Text Solution

Verified by Experts

The correct Answer is:
B
`(R_1)/(R_2)=(l_1)/((100-l_1)`
`(R_1)/(1) = (20)/(100-20)`
therefor `R_1=(20)/(80)= 0.25`
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