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The radius of the hydrogen atom in the g...

The radius of the hydrogen atom in the ground state is of the order of

A

`10^(-4) cm`

B

`10^(-5)cm`

C

`10^(-7)cm`

D

`10^(-8)cm`

Text Solution

Verified by Experts

The correct Answer is:
d
Radius of hydrogen atom,`r=(h^2epsilon_0)/(me^2`
where,
`h=6.6xx10^(-34) J-s`
`epsilon=8.85xx10^(-12)C^2Nm^(-2)`
`m=9.1xx10^(-12)kg,e=1.6xx10^(-19)C`
`therefore r=10^(-8)cm`
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