If 200 MeV of energy is released in the fission of one nucleus of `""^(236)_(92)U`, the number of nuclei that must undergo fission to release an energy of 1000 J is,

Options

A. `3.125 xx 10^(13)`
B. `6.25 xx 10^(13)`
C. `12.5 xx 10^(13)`
D. `3.125 xx 10^(14)`

Answer

A

Explanation

Energy released in fission of one nucleus is,200mev
`w = 1.6 xx 10^(-13)J`
`= 200 xx 1.6 xx 10^(-13)J`
`e = 3.2 xx 10^(-11)J`
Energy to be released is 1000J
`3.2 xx 10^(-11)J - 1 `
`1000 J - x`
`x = 1 xx 1000/(3.2 xx 10^(-11)J)`
`x = 3.125 xx 10^(13)` nucleus.