To generate power of 3.2 MW, the number of fissions of `U^(235)` per minute is (Energy released per fission 200 MeV, `1 eV = 1.6 xx 10^(-13)` J.

Options

A. `6 xx 10^(18)`
B. `6 xx 10^(17)`
C. `10^(17)`
D. `6 xx 10^(16)`

Answer

A

Explanation

Energy produced per fission = 200Mev
`E = 200 xx 1.6 xx 10^(-13)J`
`P = 3.2 MW`
`= 3.2 xx 10^(6)Js^(-1)`
`P = 3.2 xx 60 J min^(-1)`
The number of Fissions required per min
`200 xx 1.6 xx 60 rarr n`
`n = 3.2 xx 10^(6) xx 60/(200 xx 1.6 xx 10^(-13))`
`:. n = 6 xx 10^(18).`