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When ""(15)P^(30) decays to become ""(14...

When `""_(15)P^(30)` decays to become `""_(14)Si^(30)` the particle released is,

A

Electron

B

`alpha`-particle

C

Neutron

D

Positron

Text Solution

Verified by Experts

The correct Answer is:
D
`""_(15)P^(30) rarr x + _(14)Si^(30) `
`""_(15)P^(30) rarr _(+1)e^(0) + _(14)Si^(30)`
x is ` _(+1)e^(0) ` i.e., positron
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