A nuclear reactor has power of 16 kW. If the energy per fussion is 200 MeV, the number of fissions per second are,

Options

A. `5 xx 10^(16)`
B. `5 xx 10^(17)`
C. `5 xx 10^(14)`
D. `5 xx 10^(15)`

Answer

C

Explanation

Energy produced per Fission,E = 200 meV
`= 200 xx 1.6 xx 10^(-13)`J
= `3.2 xx 10^(-11)`J
Power = 16kW = `16 xx 10^(3) Js^(-1)`
Number of fission required per second
`3.2 xx 10^(-11) J rarr 1`
`16 xx 10^(3) Js^(-1) rarr n`
`n =16 xx 10^(3)/(3.2 xx 10^(-11))`
`n = 5 xx 10^(14).`