A radio station operates at a frequency of 10 MHz with a power output of 265.2 kW. Given that the Planck's constant h = `6.63 xx 10^(-34) ` J-s. The rate of emission of photon from the station is,

Options

A. `4 xx 10^(20)`
B. `4 xx 10^(31)`
C. `5 xx 10^(18)`
D. `5 xx 10^(12)`

Answer

B

Explanation

Rate of emission of photon
`n =p/(hv)`
`= 265.2xx10^(3)/(6.63xx10^(-34)xx10xx10^(6))`
`:. n = 4 xx 10^(31)`