एकसमान वृत्तीय गति करते हुए एक कण का कोणीय संवेग L है । यदि इसकी कोणीय आवृत्ति दुगनी तथा गतिज ऊर्जा आधी कर दी जाए तो नया कोणीय संवेग होगा ।

Options

A. `(L)/(4)`
B. `2L`
C. `4L`
D. `(L)/(2)`.

Answer

A

Explanation

`L=Iomega,K=(1)/(2)Iomega^(2)=(1)/(2)L.omega`
`therefore (K_(1))/(K_(2))=(L_(1))/(L_(2)).(omega_(1))/(omega_(2)) rArr (L_(1))/(L_(2))=(K_(1))/(K_(2))xx(omega_(2))/(omega_(1))`
`rArr" "(L_(1))/(L_(2))=(K_(1))/((K_(2))/(2))xx(2omega_(1))/(omega_(1))=4 rArr (L_(1))/(L_(2))=4.`