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If theta1,theta2, theta3 radians be the ...

If `theta_1,theta_2, theta_3` radians be the angles subtended by the arcs of lengths `l_1,l_2,l_3` at the centres of the circle whose radii are `r_1,r_2,r_3` respectively then show that the angle subtended at the centre by the arc of length `(l_1+l_2+l_3) ` of a circle whose radius is `(r_1+r_2+r_3)` will be `(r_1theta_1+r_2theta_2+r_3theta_3)/(r_1+r_2+r_3)` radian.

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The correct Answer is:
Then `theta=(l_1+l_2+l_3)/(r_1+r_2+r_3)= (r_1theta_1+r_2theta_2+r_3theta_3)/(r_1+r_2+r_3)` radian
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