Home
Class 12
MATHS
2 cos(pi/3 +A)=...

`2 cos(pi/3 +A)=`

A

`cosA - sqrt3sin A`

B

`cosA - sqrt2 sinA`

C

`sinA - sqrt3 cos A`

D

`sinA - sqrt2 cos A`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • TRIGONOMETRIC RATIOS OF COMPOUND ANGLES

    CHHAYA PUBLICATION|Exercise Very Short Answer type Questions|23 Videos
  • TRIGONOMETRIC RATIOS OF COMPOUND ANGLES

    CHHAYA PUBLICATION|Exercise Short Answer Type Questions|26 Videos
  • TRIGONOMETRIC RATIOS OF COMPOUND ANGLES

    CHHAYA PUBLICATION|Exercise Comprehension Type|6 Videos
  • TRIGONOMETRIC RATIOS OF ASSOCIATED ANGLES

    CHHAYA PUBLICATION|Exercise SAMPLE QUESTIONS FOR COMPETITIVE EXAMS - ASSERTION-REASON TYPE|2 Videos
  • TRIGONOMETRIC RATIOS OF MULTIPLE ANGLES

    CHHAYA PUBLICATION|Exercise Comprehension Type|6 Videos

Similar Questions

Explore conceptually related problems

Prove that : "sin"(pi)/(3) "tan"(pi)/(6) +"sin"(pi)/(2) "cos"(pi)/(3) =2 "sin"^(2)(pi)/(4) .

Prove that "cos" (3pi)/13 + "cos" (5pi)/13 - 2 "cos" (9pi)/13 "cos" (12pi)/13 = 0

The maximum and minimum values of [4 cos x^(2)cos ((pi)/(3)+ x^(2))cos ((pi)/(3)-x^(2))] respectively are-

f(x)=cos^2x+cos^2(pi/3 +x)-cosxcos(pi/3 +x) is

Period of f(x)=sin, pi/2 x+2cos, pi/3 x-tan, pi/4 x is equal to

sin ^(2)(pi/6) + cos ^(2)(pi/3) - tan ^(2)(pi/4) =- 1/2

prove: 2cos^2(pi/3)+3/4sec^2(pi/4)+4sin^2(pi/6)=cot^2(pi/6)

Solve: (x+1) cot^2 (pi/6) = 2cos^2 (pi/3)+ 3/4 sec^2 (pi/4)+ 4 sin^2 (pi/6) .

Evaluate cos^2((pi)/(3))+sin^2((pi)/6)-tan^2((pi)/4)

The value of cos ((3pi)/2 + x)cos (2pi + x){cot ((3pi)/2 - x) + cot (2pi + x)} is-