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Show that 4 sin A sin Bsin C = sin(A+B...

Show that
`4 sin A sin Bsin C = sin(A+B-C) + sin (B+C-A) + sin(C+A-B)-sin(A+B+C).`

Text Solution

Verified by Experts

The correct Answer is:
`= sin(A+B-C) + sin(B+C-A) + sin (A+C-B)-sin (A+B+C)=R.H.S`
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