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If " "a cos theta + b sin theta =c " and...

`If " "a cos theta + b sin theta =c " and " b cosec theta - a sec theta = c, " prove that" cot 2 theta = (c^(2) + a^(2) - b^(2))/(2ab)`

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The correct Answer is:
`cot 2 theta = (c^(2) + a^(2) - b^(2))/(2ab)`
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