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Show that, (sin theta)/(cos 3 theta) + (...

Show that, `(sin theta)/(cos 3 theta) + (sin 3 theta)/(cos 9 theta) + (sin 9 theta)/(cos 27 theta) = 1/2 ( tan 27 theta - tan theta).`

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The correct Answer is:
`(sin theta)/(cos 3theta) + (sin 3 theta)/(cos 9theta) + (sin 9theta)/(cos 27theta) = 1/2 [tan 27 theta - tan theta]`
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