Home
Class 12
MATHS
Prove that, 4 (cos^(3) 10^(@) + sin^(3) ...

Prove that, `4 (cos^(3) 10^(@) + sin^(3) 20 ^(@))=3 (cos 10^(@) + sin 20^(@))`

Answer

Step by step text solution for Prove that, 4 (cos^(3) 10^(@) + sin^(3) 20 ^(@))=3 (cos 10^(@) + sin 20^(@)) by MATHS experts to help you in doubts & scoring excellent marks in Class 12 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • TRIGONOMETRIC RATIOS OF MULTIPLE ANGLES

    CHHAYA PUBLICATION|Exercise Long Answer Type Questions|30 Videos

  • TRIGONOMETRIC RATIOS OF MULTIPLE ANGLES

    CHHAYA PUBLICATION|Exercise Multiple Correct Answere Type|5 Videos

  • TRIGONOMETRIC RATIOS OF MULTIPLE ANGLES

    CHHAYA PUBLICATION|Exercise Very Short Answer Type Questions|12 Videos

  • TRIGONOMETRIC RATIOS OF COMPOUND ANGLES

    CHHAYA PUBLICATION|Exercise Comprehension Type|6 Videos

  • TRIGONOMETRIC RATIOS [OR FUNCTIONS] OF POSITIVE ACUTE ANGLES

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Exams (Assertion -Reason Type )|2 Videos

Similar Questions

Explore conceptually related problems

Prove that, (cos 20^(@) + sin 20^(@))/(cos 20^(@) - sin 20^(@)) = tan 65^(@)

Prove that, (cos30^(@) - sin 20^(@))/(cos 40^(@) + cos20^(@)) = 4/sqrt3 cos40^(@) cos 80^(@)

Knowledge Check

  • The value of (cos 10^(@) + sin 10^(@))/(cos 10^(@) -sin 10^(@))is-

    A
    `tan 35^(@)`
    B
    `-cot 35^(@)`
    C
    `-tan 35^(@)`
    D
    `tan55^(@)`

    • Similar Questions

    Explore conceptually related problems

    Show that 4(cos^3 10^@+sin^3 20^@)=3(cos10^@+sin20^@)

    Prove that sin 20^(@) + sin 140^(@)-cos 10 ^(@) =0

    Prove that cos 10^(@) cos20^(@) + sin 45^(@) cos145^(@) + sin 55^(@) cos245^(@) = 0

    Prove that sin10^(@) + sin20^(@) + sin 40^(@) + sin 50^(@) = sin 70^(@) + sin 80^(@)

    Prove that cos32^(@) sin20^(@) + cos144^(@) cos2^(@) + sin68^(@) cos56^(@) = 0

    Prove the following identities: (cos10^(@)-sin10^(@))/(cos10^(@) + sin10^(@))=tan 35^(@)

    Prove that 8 sin20^(@) sin40^(@) sin80^(@) = sqrt3

    Home
    Profile