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If log(e)2.log(x)25=log(10)16.log(e )10 ...

If `log_(e)2.log_(x)25=log_(10)16.log_(e )10` find the value of x

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If log_(e)2.log_(x)25 = log_(10)16.log_(e )10 , then find the value of x.

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Knowledge Check

  • If x+log_(10)(1+2^(x))=xlog_(10)5+log_(10)6 then the value of x is

    A
    `(1)/(2)`
    B
    `(1)/(3)`
    C
    1
    D
    2

  • If f(x)=log_(x)(log_(e)x) , then the value of f'(e ) is -

    A
    0
    B
    e
    C
    `(1)/(e )`
    D
    `(1)/(e^(2))`

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    If 1/(log_(x)10) = 2/(log_(0.5)10) , then find the value of x.

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