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A student obtained the mean and standard...

A student obtained the mean and standard deviation of 100 observations as 40 and 5.1 respectively. It was later found that he had wrongly copied one observation as 50, the correct figure being 40. Calculate the correct mean and correct standard deviation.

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The correct Answer is:
Mean = 39.90 and S.D. = 5
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CHHAYA PUBLICATION-MEASURES OF DISPERSION -Exercise 3 Short answer type
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  2. Find the mean deviation from the mean for the following data :

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  3. Find the mean deviation from median of the following data :

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  4. Find the mean deviation about the median of the following frequency di...

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  5. Calculate the mean deviation from median of the following frequency di...

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  6. Calculate the mean deviation from median of the following frequency di...

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  7. Find the mean deciation about the median for the following frequency d...

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  8. Find the mean deviation about median from the following data :

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  9. Determine the mean deviation from the median for the following grouped...

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  10. Calculate the mean deviation about (a) median and (b) mean for the fol...

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  11. Calculate the average deviation from the mean for the following data :

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  12. A student obtained the mean and standard deviation of 100 observations...

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  13. The mean and the standard deviation of a characteristic of 100 items w...

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  14. Find the S.D. in respect of each of the following frequency distributi...

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  15. Find the S.D. in respect of each of the following frequency distributi...

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  16. Find the S.D. in respect of each of the following frequency distributi...

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  17. Find the S.D. of each of the following grouped frequency distributions...

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  18. Find the S.D. of each of the following grouped frequency distributions...

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  19. Find the S.D. of each of the following grouped frequency distributions...

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  20. Find the S.D. of each of the following grouped frequency distributions...

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