Home
Class 12
MATHS
The common chord of the circles x^(2)+y^...

The common chord of the circles `x^(2)+y^(2)-4x-4y=0and2x^(2)+2y^(2)=32` subtends at the origin an angle equal to

A

`(pi)/(3)`

B

`(pi)/(4)`

C

`(pi)/(6)`

D

`(pi)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS EXAMPLES

    CHHAYA PUBLICATION|Exercise WBJEE ARCHIVE 2017 (UNIT-7)|1 Videos

  • MISCELLANEOUS EXAMPLES

    CHHAYA PUBLICATION|Exercise HS (XI) AND WBJEE 2018 (GROUP - A)|10 Videos

  • MISCELLANEOUS EXAMPLES

    CHHAYA PUBLICATION|Exercise WBJEE ARCHIVE 2017 (UNIT-3)|13 Videos

  • METHOD OF SUBSTITUTION

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Examination (Assertion-Reason Type)|2 Videos

  • ORDER AND DEGREE OF DIFFERENTIAL EQUATION

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Examination (E Assertion - Reasion Type )|2 Videos

Similar Questions

Explore conceptually related problems

The common chord of x^2+y^2-4x-4y=0 and x^2+y^2=16 subtends at the origin an angle equal to

Find the equation to the circle described on the common chord of the circles x^(2) + y^(2) - 4x - 2y - 31 = 0 and 2x^(2) + 2y^(2) - 6x + 8y - 35 = 0 as diameter.

Find the equation to the common chord of the two circles x^(2) + y^(2) - 4x + 6y - 36 = 0 and x^(2) + y^(2) - 5x + 8y - 43 = 0 .

Find the equation of the common chord of the two circles x^(2)+y^(2)-4x - 10y - 7 = 0 and 2x^(2) + 2y^(2) - 5x + 3y + 2 = 0 . Show that this chord is perpendicular to the line joining the centres of the two circles.

Find the equation to the circle described on the common chord of the given circles x^(2) + y^(2) - 4x - 5 = 0 and x^(2) + y^(2) + 8x + 7 = 0 as diameter.

Find the equation of the common chord of the two circles x^(2) + y^(2) - 4x - 2y - 31 = 0 and 2x^(2) + 2y^(2) - 6x + 8y - 35 = 0 and show that this chord is perpendicular to the line joining the two centres.

The locus of the midpoints of chords of the circle x^(2) + y^(2) = 1 which subtends a right angle at the origin is

The length of the common chord of the two circles x^2+y^2-4y=0 and x^2+y^2-8x-4y+11=0 is

A circle through the common points of the circles x^(2) + y^(2) - 2x - 4y + 1 = 0 and x^(2) + y^(2) - 2x - 6y + 1 = 0 has its centre on the line 4x - 7y - 19 = 0 . Find the centre and radius of the circle .

The common chord of the circle x^2+y^2+6x+8y-7=0 and a circle passing through the origin and touching the line y=x always passes through the point. (a) (-1/2,1/2) (b) (1, 1) (c) (1/2,1/2) (d) none of these