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The chord of the curve y=x^2+2ax+b, join...

The chord of the curve `y=x^2+2ax+b`, joining the points where `x=alpha " and " x=beta`, is parallel to the tangent to the curve at abscissa x=

A

`(a+b)/(2)`

B

`(2a+b)/(3)`

C

`(2alpha+beta)/(3)`

D

`(alpha+beta)/(2)`

Text Solution

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The correct Answer is:
D
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CHHAYA PUBLICATION-QUESTION PAPER 2017-UNIT-3
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