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If the straight line lx+my=n is a normal...

If the straight line `lx+my=n` is a normal to the hyperbola `(x^(2))/(a^(2))-(y^(2))/(b^(2))=1` show that `(a^(2))/(l^(2))-(b^(2))/(m^(2))=((a^(2)+b^(2))^(2))/(n^(2))`.

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The correct Answer is:
`(a^(2))/(l^(2))-(b^(2))/(m^(2))= ((a^(2)+b^(2))^(2))/(n^(2))`
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