Prove that the curves `y^(2) =4ax and x^(2) =4ay ` divide the square bounded by ` x=0 ,y=0 ,x=4a `and y=4a into three equal parts.

Prove that the curves y^(2) =4x" and "x^(2)= 4y divide the area of the square bounded by x= 0, x= 4, y =4 and y= 0 into three equal parts.

The parabolas y^(2)= 4x and x^(2) = 4y divide the square region bounded by the line x = 4 , y = 4 and the coordinate axes into three parts. If S_(1), S_(2), S_(3) are respectively the areas of these three parts numbered from top to bottom then S_(1) : S_(2) : S_(3) is-

The parabolas y^(2) =4x and x^(2) =4y divide the square region bounded by the lines x=4,y=4 and the coordinates axes. If S_1 ,S_2, S_3 are the areas of these parts numbered from the top to bottom respectively,then-

Find the area bounded by the curve x^2=y ,x^2=-y and y^2=4x-3

If the area bounded by the curves y^2 = 4ax and x^2 = 4ay is (16a^2)/3 sq- unit then find the area bounded by y^2 = 2x and x^2 = 2y

Mark the area bounded by the curves y^2= 4x and x^2= 4y and find the marked area.

Find the area of the region bounded by x^(2) = 4y, y = 2, y = 4 and the y-axis in the first quadrant.

Find the area bounded by the curves x^2+y^2=25 ,4y=|4-x^2|, and x=0 above the x-axis.

Find the area bounded by the curve x^(2) = 4y and the line x = 4y - 2.