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The volume and temperature of 2 mol of a...

The volume and temperature of 2 mol of an ideal gas are 10 L & `27^(@)C`, respectively. The gas is allowed to expand in an isothermal reversible process to attain a final volume of 25 L. calculate the maximum work done.

Text Solution

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We know tha maximum work is obtained in a revesible isothermal expansion.
Now, work done by an ideal gas in an isothermal reversible expansion, `w=-nRT "ln"(V_(2))/(V_(1))`.
Given: n=2, T=(273+27)=300K, `V_(1)=10L,V_(2)=25L`
`therefore w=[-2xx8.314xx300"ln"(25)/(10)]J=-4570.82J`
`therefore`The maximum work done by the `gas=4570.82J`.
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